(2x-1)(3x^2-x-4)=0

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Solution for (2x-1)(3x^2-x-4)=0 equation:


Simplifying
(2x + -1)(3x2 + -1x + -4) = 0

Reorder the terms:
(-1 + 2x)(3x2 + -1x + -4) = 0

Reorder the terms:
(-1 + 2x)(-4 + -1x + 3x2) = 0

Multiply (-1 + 2x) * (-4 + -1x + 3x2)
(-1(-4 + -1x + 3x2) + 2x * (-4 + -1x + 3x2)) = 0
((-4 * -1 + -1x * -1 + 3x2 * -1) + 2x * (-4 + -1x + 3x2)) = 0
((4 + 1x + -3x2) + 2x * (-4 + -1x + 3x2)) = 0
(4 + 1x + -3x2 + (-4 * 2x + -1x * 2x + 3x2 * 2x)) = 0
(4 + 1x + -3x2 + (-8x + -2x2 + 6x3)) = 0

Reorder the terms:
(4 + 1x + -8x + -3x2 + -2x2 + 6x3) = 0

Combine like terms: 1x + -8x = -7x
(4 + -7x + -3x2 + -2x2 + 6x3) = 0

Combine like terms: -3x2 + -2x2 = -5x2
(4 + -7x + -5x2 + 6x3) = 0

Solving
4 + -7x + -5x2 + 6x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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